Q. 74.8( 11 Votes )

Construct a ΔABC

Answer :

Steps of Construction:

1. Draw a line segment BC of length 8cm.

2. Make an angle of 45° from B and an angle of 60° from C. The point where the rays meet is point A.

3. Draw a ray BY making an acute angle with the line BC. Make 5 equal arcs starting from B, then B1 and so on till B5.

4. Join B5C.

5. As we have to get the triangle 3/5 times of this triangle ABC.

6. From B3, draw a line parallel to B5C cutting BC at C’.

7. Draw another line from C’ parallel to AC cutting AB at A’.

8. A’BC’ is our required triangle.

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