Answer :

It is given in the question that the nth term of the series,

an = 2n2 – 3n + 5

Now, we need to find the sum of this series, Sn.


I. Sum of first n natural numbers, 1 + 2 +3+…n,

II. Sum of squares of first n natural numbers, 12 + 22 + 32+….n2,

III. Sum of cubes of first n natural numbers, 13 + 23 + 33 +…..n3,

IV. Sum of a constant k, N times,

So, for the given series, we need to find,

Hence, the sum of the series,

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