Answer :
It is given in the question that the nth term of the series,
an = n (n + 1) (n + 4)
Now, we need to find the sum of this series, Sn.
=
=
Note:
I. Sum of first n natural numbers, 1 + 2 +3+…n,
II. Sum of squares of first n natural numbers, 12 + 22 + 32+….n2,
III. Sum of cubes of first n natural numbers, 13 + 23 + 33 +…..n3,
IV. Sum of a constant k, N times,
So, for the given series, we need to find,
From the above identities,
Hence, the Sum of the series,
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation


RELATED QUESTIONS :
A person has 2 pa
RD Sharma - MathematicsThe sum of the se
RD Sharma - MathematicsHow many terms of
RD Sharma - MathematicsIf <span lang="EN
RD Sharma - MathematicsLet an
RD Sharma - MathematicsFind the sum of 2
RD Sharma - MathematicsIf <span lang="EN
RS Aggarwal - MathematicsFind the sum (41
RS Aggarwal - MathematicsFind the sum (2 +
RS Aggarwal - MathematicsIf<span lang="EN-
RS Aggarwal - Mathematics