Q. 24.4( 159 Votes )

# Find the amount of water displaced by a solid spherical ball of diameter

(i) 28 cm

(ii) 0.21 m

Answer :

**Note: **when a ball is dropped in any container, the volume of water displaced is

same as volume of sphere as now sphere has taken the place of water. **(i)d =28 cm**As,

r = d/2

= 28/2

Radius (r) = 14 cm

Volume of water displaced = Volume of Sphere = πr^{3}

= × × (14)^{3}

= × 22 × 2 × 14 × 14

= cm^{3}

**(ii)** **d = 0.21 m**

As,

r = d/2

= 0.21/2

Radius (r) = 0.105 m

Volume of water displaced** =**Volume of Sphere = πr^{3}

= × × (0.105)^{3}

= 0.004851 m^{3}

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