Answer :

**(i)** Rs 20 is the cost of painting 1 m^{2} area Rs 2200 is the cost of painting = ( × 2200) m^{2}

= 110 m^{2}

Therefore, the inner surface area of the vessel is 110 m^{2}

**(ii)** Let the radius of the base of the vessel be r

Height (h) = 10 m

Surface Area = 2πrh = 110 m^{2}

= 2 × × r × 10 = 110

= r = m

r = 1.75 m

**(iii)** Volume = πr^{2}h

= × 1.75 × 1.75 × 10

= 96.25 m^{3}

The capacity of the vessel is 96.25 m^{3} or 96250 litres

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