Answer :

Given:

Radius (*r*1) of upper circular end of frustum part = = 9 cm

Radius (*r*2) of lower circular end of frustum part = Radius of circular end of cylindricalpart = = 4 cm

Height (*h*1) of frustum part = 22 - 10 = 12 cm

Height (*h*2) of cylindrical part = 10 cm

Slant height (*l*) of frustum part

=

= 13 cm

Area of tin sheet required = CSA of frustum part + CSA of cylindrical part

= π (r1 + r2) * l + 2πr2h2

= (9 + 4) * 13 + 2 * * 4 * 10

= [169 + 80]

=

= 782 cm^{2}

Rate this question :

How useful is this solution?

We strive to provide quality solutions. Please rate us to serve you better.

Related Videos

Trigo Marathon Part 146 mins

Trigo Marathon Part 245 mins

Application of Trigo Important Questions44 mins

History - Concept and Questions57 mins

Chemical Properties of Metal and Non Metal61 mins

Arithmetic Progression and 'nth' Term of AP55 mins

Heights and Distances - I54 mins

Heights and Distances - II45 mins

Extraction of Metal56 mins

Purification of Metals60 mins

Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Expertsview all courses

Dedicated counsellor for each student

24X7 Doubt Resolution

Daily Report Card

Detailed Performance Evaluation