Q. 13.6( 38 Votes )

A die is thrown 6

Answer :

We know that the repeated tosses of a dice are known as Bernouli trials.

Let the number of successes of getting an odd number in an experiment of 6 trials be x.


Probability of getting an odd number in a single throw of a dice(p)


Thus,


Now, here x has a binomial distribution.


Thus, P(X = x) = nCxqn-xpx , where x = 0, 1, 2, …n


= 6Cx (1/2)6-x(1/2)x


= 6Cx (1/2)6


(i) Probability of getting 5 successes = P(X = 5)


= 6C5(1/2)6




(ii) Probability of getting at least 5 successes = P(X ≥ 5)


= P(X = 5) + P(X = 6)


= 6C5(1/2)6 + 6C5 (1/2)6





(iii) Probability of getting at most 5 successes = P(X ≤ 5)


We can also write it as: 1 – P(X>5)


= 1 – P(X = 6)


= 1 – 6C6 (1/2)6




Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

A box has 100 penMathematics - Exemplar

State True or FalMathematics - Exemplar

A random variableMathematics - Board Papers

How many times muMathematics - Board Papers

A card from a pacMathematics - Board Papers

An experiment sucMathematics - Board Papers

A bag A contains Mathematics - Board Papers

On a multiple choMathematics - Board Papers

Mark the correct RD Sharma - Volume 2