Answer :
The inner radius of hemispherical bowl = 5 cm
The thickness of the bowl = 0.25 cm
Outer radius (r) of hemispherical bowl = (5 + 0.25) cm
= 5.25 cm
Outer CSA of hemispherical bowl = 2πr2
= 2 × 
× (5.25)2
= 173.25 cm2
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