Answer :

The figure is given below:


In ΔAEG,

⇒ EG = tan 300 × AG

⇒ EG = (1/√3)× 10 cm      [tan 30° = 1/√3]

⇒ EG =

In ΔABD,

= tan 30o

⇒ BD = tan 300 × AD

⇒ BD =(1/√3)× 20 cm

⇒ BD =   

⇒ BD =

Radius (r1) = cm

Radius (r2) = cm

Height (h) = 10 cm

Volume of frustum = (1/3)πh (r12 + r22 + r1r2)

=  x π x 10 [()2 + ()2 + ]

= [ + + ]

=  x  x 

= cm3

Radius (r) of wire = x  = cm

Let the length of wire be l.

Volume of wire = Area of cross-section × Length

= (πr2) (l)

= π x ()2 * l

Volume of frustum = Volume of wire

=  x ()2 * l

 x 1024 = l

l = 796444.44 cm

= 7964.44 meters

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