Answer :
The figure is given below:
In ΔAEG,
⇒ EG = tan 300 × AG
⇒ EG = (1/√3)× 10 cm [tan 30° = 1/√3]
⇒ EG =
In ΔABD,
= tan 30o
⇒ BD = tan 300 × AD
⇒ BD =(1/√3)× 20 cm
⇒ BD =
⇒ BD =
Radius (r1) = cm
Radius (r2) = cm
Height (h) = 10 cm
Volume of frustum = (1/3)πh (r12 + r22 + r1r2)
= x π x 10 [(
)2 + (
)2 +
]
= [
+
+
]
= x
x
= cm3
Radius (r) of wire = x
=
cm
Let the length of wire be l.
Volume of wire = Area of cross-section × Length
= (πr2) (l)
= π x ()2 * l
Volume of frustum = Volume of wire
=
x (
)2 * l
x 1024 = l
l = 796444.44 cm
= 7964.44 meters
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