A metallic right

The figure is given below:

In ΔAEG,

⇒ EG = tan 30⁰ × AG

⇒ EG = (1/√3)× 10 cm      [tan 30° = 1/√3]

⇒ EG =

In ΔABD,

= tan 30^o

⇒ BD = tan 30⁰ × AD

⇒ BD =(1/√3)× 20 cm

⇒ BD =   

⇒ BD =

Radius (r₁) = cm

Radius (r₂) = cm

Height (h) = 10 cm

Volume of frustum = (1/3)πh (r₁² + r₂² + r₁r₂)

=  x π x 10 [()² + ()² + ]

= [ + + ]

=  x  x 

= cm³

Radius (r) of wire = x  = cm

Let the length of wire be l.

Volume of wire = Area of cross-section × Length

= (πr²) (l)

= π x ()² * l

Volume of frustum = Volume of wire

=  x ()² * l

 x 1024 = l

l = 796444.44 cm

= 7964.44 meters