# There are three c

Given: let E1 be the event of choosing a two headed coin, E2 be the event of choosing a biased coin and E3 be the event of choosing an unbiased coin. Let A be the event that the coin shows head.

Then P (E1) = P (E2) = P (E3) = 1/3

Also P(A|E1) = P (correct answer given that he knows) = 1

And P(A|E2) = P (coin shows head given that the coin is biased) And P(A|E3) = P (coin shows head given that the coin is unbiased) Now the probability that the coin is two headed, being given that it shows head, is P(E1|A).

By using bayes’ theorem, we have:     Rate this question :

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