Answer :

The shape of the well will be cylindrical.

Depth (h1) of well = 14 m

Radius (r) of the circular end of well = 3/2 m

Width of embankment = 4 m

As per the question,
Our embankment will be in a cylindrical shape having outer radius (R)as 11/2 m and inner radius (r) = 3/2 m

Let the height of embankment be h2

Volume of soil dug from well = Volume of earth used to form embankment

πr2 × h1 = π × (R2 – r2) × h2

⇒ 31.5  = 28 h

⇒ h = 1.125 m

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