Q. 24.3( 41 Votes )

A bag contains 4

Answer :

Given: let E1 be the event of choosing the bag I, E2 be the event of choosing the another bag say bag II and A be the event of drawing a red ball.

Then P (E1) = P (E2) = 1/2


Also P(A|E1) = P (drawing a red ball from bag I)


And P(A|E2) = P (drawing a red ball from bag II)


Now the probability of drawing a ball from bag I, being given that it is red, is P(E1|A).


By using bayes’ theorem, we have:







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