Answer :
The diameter of a circular park = 42m
⇒ the radius of a circular park,
Width of path = 3.5m
⇒ radius of the park with path, R = 21 + 3.5 = 24.5m
∴ Area of path = Area of outer circle – Area of the inner circle
= πR2 – πr2
= π (R2 – r2)
= π (R – r)(R + r)
= 22 × 0.5 × 45.5
= 500.5 m2
Now, the cost of gravelling the path of 1m2 = Rs 4
the cost of gravelling the path of 500.5m2 = Rs 4×500.5
= Rs 2002
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