Answer :

Given: let E_{1} be the event of time consumed by machine A, E_{2} be the event of time consumed by machine B and E_{3} be the event of time consumed by machine C. Let X be the event of producing defective items.

Then

And

And

As we a headed coin has head on both sides so it will shows head.

Also P(X|E_{1}) = P (defective item produced by A)

And P(X|E_{2}) = P (defective item produced by B)

And P(X|E_{3}) = P (defective item produced by C)

Now the probability that item produced by machine A, being given that defective item is produced, is P(E_{1}|A).

By using bayes’ theorem, we have:

Rate this question :

A bag A contains RD Sharma - Volume 2

The contents of tRD Sharma - Volume 2

A girl throws a dMathematics - Board Papers

Three urns contaiRD Sharma - Volume 2

Two groups are coMathematics - Board Papers

The contents of tRD Sharma - Volume 2

Suppose a girl thMathematics - Board Papers

There are three cMathematics - Board Papers

Given three identMathematics - Board Papers