Q. 114.1( 22 Votes )

A manufacturer ha

Answer :

Given: let E1 be the event of time consumed by machine A, E2 be the event of time consumed by machine B and E3 be the event of time consumed by machine C. Let X be the event of producing defective items.

Then


And


And


As we a headed coin has head on both sides so it will shows head.


Also P(X|E1) = P (defective item produced by A)


And P(X|E2) = P (defective item produced by B)


And P(X|E3) = P (defective item produced by C)


Now the probability that item produced by machine A, being given that defective item is produced, is P(E1|A).


By using bayes’ theorem, we have:







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