Q. 104.6( 33 Votes )

Suppose a girl th

Answer :

Given: : let E1 be the event that the outcome on the die is 5 or 6, E2 be the event that the outcome on the die is 1, 2, 3 or 4 and A be the event getting exactly head.

Then


And


As in throwing a coin three times we get 8 possibilities.


{HHH, HHT, HTH, THH, TTH, THT, HTT, TTT}


P(A|E1) = P (obtaining exactly one head by tossing the coin three times if she get 5 or 6)


And P(A|E2) = P (obtaining exactly one head by tossing the coin three times if she get 1,2 ,3 or 4)


Now the probability that the girl threw 1, 2, 3 or 4 with a die, being given that she obtained exactly one head, is P(E2|A).


By using bayes’ theorem, we have:







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