# A circle is inscr

from the given figure

PQR is a right-angle triangle

PQ = 8 cm

QR = 6 cm

PR2 = PQ2 + QR2

PR2 = 82 + 62

PR = √100 = 10 cm

Radius of the incircle (r) = = = = 2 CM

area of coloured region = Area of triangle - area of circle

= × PQ × QR - π r2

= × 8 × 6 - π 22

= 24 – 12.566

= 11.433 cm2

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