Answer :
Given: P (A) =, P (B) =
and P (A ∩ B) =
P(not A and not B) = P(A’ ∩ B’)
As, { A’ ∩ B’ =(A ∪ B)’}
⇒ P(not A and not B) = P ((A ∪ B)’)
= 1 - P (A ∪ B)
= 1- [P(A) + P(B) - P (A ∩ B)]
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation


RELATED QUESTIONS :
Coloured balls ar
Mathematics - Board PapersIf A and B are tw
Mathematics - Board PapersState True or Fal
Mathematics - ExemplarState True or Fal
Mathematics - ExemplarState True or Fal
Mathematics - ExemplarState True or Fal
Mathematics - ExemplarState True or Fal
Mathematics - ExemplarProve that if E a
Mathematics - Board PapersState True or Fal
Mathematics - Exemplar