Answer :





Height (h) of cylindrical tank = 4.5 m

Radius (r) = () = 2.1 m


(i) Lateral or curved surface area of tank = 2πrh


= 2 ×  × 2.1 × 4.5


= (44 × 0.3 × 4.5) m2


= 59.4 m2


Therefore, the CSA of the tank is 59.4 m2.


(ii) Total surface area of tank = 2πr (r + h)


= 2 ×  × 2.1 × (2.1 + 4.5) m2


= (44 × 0.3 × 6.6) m2


= 87.12 m2


Let x m2 steel sheet be actually used in making the tank


 of steel was wasted.

TSA = amount of steel - the amount of steel used

87.12 m2= x -  x

x (1 - ) = 87.12 m2


x = ( × 87.12) m2


x = 95.04 m2


Therefore, 95.04 m2 steel was used in making such a tank.

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