Answer :

Inner diameter of the circular well = 3.5 m

Inner radius (r) of circular well = Diameter/ 2= m

= 1.75 m

Depth (h) of circular well = 10 m

**(i)** Inner curved surface area = 2πrh

= 2 x x 1.75 x 10 m^{2}

= (44 × 0.25 × 10) m^{2}

= 110 m^{2}

**Therefore, the inner curved surface area of the circular well is 110 m ^{2}**.

**(ii)** Cost of plastering 1 m^{2} area = Rs 40

Cost of plastering 110 m^{2} area = Rs (110 × 40)

= Rs 4400

**Therefore, the cost of plastering the CSA of this well is Rs 4400.**

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