Answer :

radius of the circle (r) = 42 cm


angle of measure (θ) = 60o


area of the segment =


=


= 923.16 cm2


since the center angle of measure is 60o that is a equilateral triangle.


side of the triangle (a) = 42 cm


area of the equilateral triangle =


=


= 762.93 cm2


area of minor segment (BDC) = area of segment – area of triangle


= 923.16 – 762.93


= 160.23 cm2



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