Q. 75.0( 3 Votes )

# A chord of a circ

Answer :

radius of the circle (r) = 42 cm

angle of measure (θ) = 60^{o}

area of the segment =

=

= 923.16 cm^{2}

since the center angle of measure is 60^{o} that is a equilateral triangle.

side of the triangle (a) = 42 cm

area of the equilateral triangle =

=

= 762.93 cm^{2}

area of minor segment (BDC) = area of segment – area of triangle

= 923.16 – 762.93

= 160.23 cm^{2}

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