Given an angle of 90° and chord 5cm
Steps of construction:
x + x + 90° = 180°
[using sum of all angles in a triangle = 180°]
⇒ 2x + 90° = 180°
⇒ 2x = 180° - 90°
⇒ 2x = 900°
⇒ x = = 45°
Step 1: Draw a line segment AB = 5cm
Step 2: Draw an angle of 45° on point A and B to intersect at O.
Step 3: With centre ‘O’ and radius OA and OB, draw the circle.
Step 4: Mark a point ‘C’ on the arc of the circle. Join AC and BC.
we get ∠CAB = 90°.
Thus, ACB is the required circle segment.
Rate this question :
Construct an equiAP- Mathematics
Construct PQR inAP- Mathematics
Construct ∆XYZ inAP- Mathematics
Draw the followinAP- Mathematics
Construct an isosAP- Mathematics
Construct a rightAP- Mathematics
Construct ∆ABC inAP- Mathematics