Q. 54.0( 44 Votes )

For the function

Answer :

Given function is





Since,




At x = 0


f’(0) = 0 + 0 + … + 0 + 1


f’(0) = 1


At x = 1


f’(1) = 199 + 198 + … + 1 + 1 = [1 + 1 ….+ 1] 100 times = 1 × 100 = 100


Thus f’(1) = 100 f’(0)


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