Answer :

(i) We have,

108 × 192

We have to express this as a product of prime factors only in exponential form

∴ 108 × 192

= (2 × 2 × 3 × 3 × 3) × (2 × 2 × 2 × 2 × 2 × 2 × 3)

= (2^{2} × 3^{3}) × (2^{6} × 3)

Using identity: (a^{m} × a^{n} = a^{m + n})

= 2^{6 + 2} × 3^{3 + 1}

= 2^{8} × 3^{4}

(ii) We have,

270

We have to express this as a product of prime factors only in exponential form

Thus,

270

= 2 × 3 × 3 × 3 × 5

= 2 × 3^{3} × 5

(iii) We have,

729 × 64

We have to express this as a product of prime factors only in exponential form

Thus,

729 × 64

= (3 × 3 × 3 × 3 × 3 × 3) × (2 × 2 × 2 × 2 × 2 × 2)

= 3^{6} × 2^{6}

(iv) We have,

768

We have to express this as a product of prime factors only in exponential form

Thus, 768 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 3

= 2^{8} × 3

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