Given base(BC) = 7.5cm and AB + AC = 15cm and ∠B = 90°
Steps of construction:
Step 1: Draw the base BC = 7.5cm
Step 2: Make an ∠XBC = 90° at the point B of base BC.
Step 3: Cut the line segment BD equals to AB + AC i.e. 15cm from the ray
Step 4: Join DC and make an angle bisector of ∠DCB.
Step 5: Let Y intersect BX at A.
Thus, ΔABC is the required triangle.
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