Answer :

In the given figure,


Let O be the centre of the circle


Join OS


Let O be the centre of the circle


So SRQ = 90° [radius is perpendicular to tangent]


So SRT = 90 – 30


= 60°


STR = 90° [angle in a semicircle is 90°]


RSY = 90° [radius is perpendicular to tangent]


RST + STR + SRT = 180° [sum of internal angles in a triangle is 180°]


RST + 90 + 60 = 180


RST = 180 – 150


RST = 30°


TSY = RSY - RST


= 90 – 30


= 60°


TSY = 60°


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