# A metal pipe is 77 cm long. The inner diameter of a cross section is 4 cm, the outer diameter being 4.4 cm. Find its(i) Inner curved surface area,(ii) Outer curved surface area,(iii) Total surface area

Height = Length = 77 cm

Curved Surface Area of Cylinder = 2 π r h

(i) C S A of inner surface of pipe = 2 π r1 h

(ii) CSA of outer surface of pipe = 2 π r2 h

=2×22×2.2×11
=1064.8 cm2

(iii) TSA = Inner CSA + Outer CSA + Area of both circular ends of pipe

= 2 π r1 h + 2 π r2 h + 2 π (r2 2 – r1 2)

= [968 + 1064.8 + 2π {(2.2)2 - (2)2}] cm2

= (2032.8 + 2 x  x 0.84) cm2

= (2032.8 + 5.28) cm2

= 2038.08 cm2

Therefore, the total surface area of the cylindrical pipe is 2038.08 cm2

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