# The volume of a cube is increasing at the rate of 9 cm3/sec. How fast is the surface area increasing when the length of an edge is 10 cm?

Let x be the edge of the cube, V be the volume of the cube at any instant of the time.

We know,

V = x3

Differentiating the above equation with respect to time, we get  But is is given that the volume of the cube is increasing at the rate of 9cm3/sec, so the above equation becomes,  We also know that the surface area of the cube is

S = 6x2

Again differentiating the above equation with respect to time is  Substitute equation (ii) in above equation, we get  When the edge is of length 10 cm, we get Hence the rate at which the surface area increasing when the length of an edge is 10 cm is 3.6 cm2/sec

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