Answer :


Given the rate of repair work per m2 = Rs. 25


The radius of the outer circle (R1) = 63 cm


radius of the inner circle (R2) = 63 – 7


= 56 cm


( the distance between the inner circle and outer circle is 7 cm)


Let the measured angle is 60o


area of the repair road = () – ()


= () – (


= 436.15 m2


cost required to repair the road = 436.15 × 25


= Rs. 10,903.9445 (approximately)


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