Q. 24.0( 8 Votes )

# In the figure, if ∠BAC = 80° then find the value of ∠BCP.

Answer :

AC is the diameter

∠ ACP = 90° [radius is perpendicular to tangent]

∠ ABC = 90° [angle in a semicircle is 90°]

∠ ABC + ∠ BAC + ∠ ACB = 180° [sum of internal angles in a triangle is 180°]

∠ ACB + 90° + 80° = 180°

∠ ACB = 180 – 170

∠ ACB = 10°

∠ BCP = ∠ ACP - ∠ ACB

= 90 – 10

= 80°

∴ ∠ BCP = 80°

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PREVIOUSAnswer the following questions from the figure.(i) Alternate segment of ∠BAQ.(ii) Alternate segment of ∠DAP.(iii) If C is jointed to B, then ∠ACB is equal to which angles?(iv) ∠ABD and ∠ADB are equal to which angles?NEXTIn the figure, PQ and XY are parallel tangents. If ∠QRT = 30°, then find the value of ∠TSY.

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RELATED QUESTIONS :

In the figure, PQ and XY are parallel tangents. If ∠QRT = 30°, then find the value of ∠TSY.

Rajasthan Board Mathematics

In the figure, if ∠BAC = 80° then find the value of ∠BCP.

Rajasthan Board Mathematics