Q. 24.0( 8 Votes )
In the figure, if ∠BAC = 80° then find the value of ∠BCP.

Answer :
AC is the diameter
∠ ACP = 90° [radius is perpendicular to tangent]
∠ ABC = 90° [angle in a semicircle is 90°]
∠ ABC + ∠ BAC + ∠ ACB = 180° [sum of internal angles in a triangle is 180°]
∠ ACB + 90° + 80° = 180°
∠ ACB = 180 – 170
∠ ACB = 10°
∠ BCP = ∠ ACP - ∠ ACB
= 90 – 10
= 80°
∴ ∠ BCP = 80°
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
PREVIOUSAnswer the following questions from the figure.(i) Alternate segment of ∠BAQ.(ii) Alternate segment of ∠DAP.(iii) If C is jointed to B, then ∠ACB is equal to which angles?(iv) ∠ABD and ∠ADB are equal to which angles?NEXTIn the figure, PQ and XY are parallel tangents. If ∠QRT = 30°, then find the value of ∠TSY.
Related Videos
Areas Related to Circle36 mins
Tangent from an External Point54 mins
Quiz | Imp. Qs. on Circle35 mins
Champ Quiz | Area Related with the Circle45 mins
Consistent and Inconsistent Equations33 mins
Verb & Tenses46 mins
Electronic Configuration and Valency47 mins
Learn to Make Your Own Acid Rain and pH Paper at Home!27 mins
Champ Quiz | Electrical Power and Heating31 mins
Surface Area and Volume49 mins




















Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation


RELATED QUESTIONS :
In the figure, PQ and XY are parallel tangents. If ∠QRT = 30°, then find the value of ∠TSY.
In the figure, if ∠BAC = 80° then find the value of ∠BCP.