Q. 24.0( 8 Votes )

In the figure, if BAC = 80° then find the value of BCP.


Answer :

AC is the diameter

ACP = 90° [radius is perpendicular to tangent]


ABC = 90° [angle in a semicircle is 90°]


ABC + BAC + ACB = 180° [sum of internal angles in a triangle is 180°]


ACB + 90° + 80° = 180°


ACB = 180 – 170


ACB = 10°


BCP = ACP - ACB


= 90 – 10


= 80°


BCP = 80°


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