Given: Base QR = 8 cm, PQ-PR = 3.5cm and
∠Q = 60° of Δ PQR.
Required: To construct a triangle PQR.
Steps of construction:
Step 1: Draw a segment QR of length 8cm.
Step 2: Draw ray QL such that ∠Q = 60°
Step 3: Mark an arc on opposite ray QL i.e. QS cutting at D such that QD = 3.5cm.
Step 4: Draw segment RD.
Step 5: Construct the perpendicular bisector of segment RD.
Step 6: Name the point of intersection of ray QL and the perpendicular bisector of RD as P.
Step 7: Draw segment PR.
ΔPQR is the required triangle.
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