Answer :

Given: Base QR = 8 cm, PQ-PR = 3.5cm and

∠Q = 60° of Δ PQR.

Required: To construct a triangle PQR.

Steps of construction:

Step 1: Draw a segment QR of length 8cm.

Step 2: Draw ray QL such that ∠Q = 60°

Step 3: Mark an arc on opposite ray QL i.e. QS cutting at D such that QD = 3.5cm.

Step 4: Draw segment RD.

Step 5: Construct the perpendicular bisector of segment RD.

Step 6: Name the point of intersection of ray QL and the perpendicular bisector of RD as P.

Step 7: Draw segment PR.

ΔPQR is the required triangle.

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