Given: base BC = 7cm, AB + AC = 12 cm and
∠B = 75° of Δ ABC.
Required: To construct a ΔABC
Steps of construction:
Step 1: Draw a segment BC of length of 7 c
Step 2: At vertex B, construct ∠B = 75° and produce a ray BP.
Step 3: Mark an arc on ray BP cutting at D such that BD = 12cm.
Step 4: Draw segment CD.
Step 5: Construct the perpendicular bisector of segment CD.
Step 6: Name the point of intersection of ray BP and the perpendicular bisector of CD as A.
Step 7: Draw segment AB.
ΔABC is the required triangle.
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