Answer :

Given:

Height (h) of the conical part = Height (h) of the cylindrical part = 2.4 cm


Diameter of the cylindrical part = 1.4 cm


Radius (r) of the cylindrical part = 0.7 cm
we know, slant height of cone, l = √(r2 + h2)


Slant height of the cylindrical part (l) = 


=


=


= 2.5


Total surface area of the remaining solid will be


= CSA of cylindrical part + CSA of conical part + Area of cylindrical base


= 2πrh + πrl + πr2


=( 2 ×  × 0.7 × 2.4 )+(  × 0.7 × 2.5) +(  × 0.7 × 0.7)


= (4.4 × 2.4) +( 2.2 × 2.5) +( 2.2 × 0.7)


= 10.56 + 5.50 + 1.54


= 12.10 + 5.50 cm2
= 17.60 cm2 (approx)
Hence, the total surface area of remaining solid is 17.60 cm2.

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