Q. 34.2( 20 Votes )
In a simultaneous throw of a pair of dice, find the probability of getting:
(i) 8 as the sum
(ii) a doublet
(iii) a doublet of prime numbers
(iv) a doublet of odd numbers
(v) a sum greater than 9
(vi) an even number on first
(vii) an even number on one and a multiple of 3 on the other
(viii) neither 9 nor 11 as the sum of the numbers on the faces
(ix) a sum less than 6
(x) a sum less than 7
(xi) a sum more than 7
(xii) at least once
(xiii) a number other than 5 n any dice.
(xiv) even number on each die
(xv) 5 as the sum
(xvi) 2 will come up at least once
(xvii) 2 will not come either time
Answer :
Sample space = 36
(i) n(E) = 5
(ii) n(E) = 6
(iii) n(E) = 3
(iv) 
(v) 
(vi) 
(vii) 
(viii) Number of event with sum 9 or 11 = 6
∴ Number of events of not getting a sum of either 9 or 11 = 36 – 6 = 30
(ix) 
(x) 
(xi) 
(xii) 
(xiii) 
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PREVIOUSA die is thrown. Find the probability of getting:(i) a prime number(ii) 2 or 4(iii) a multiple of 2 or 3(iv) an even prime number(v) a number greater than 5(vi) a number lying between 2 and 6NEXTThree coins are tossed together. Find the probability of getting:(i) exactly two heads(ii) at most two heads(iii) at least one head and one tail.(iv) no tails
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RELATED QUESTIONS :
Which of the following amongst the given options cannot be the probability of an event:
(i) 1.01 (ii) 67%
(iii) -0.5 (iv) 
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KC Sinha - Mathematics