# In a simultaneous throw of a pair of dice, find the probability of getting:(i) 8 as the sum(ii) a doublet(iii) a doublet of prime numbers(iv) a doublet of odd numbers(v) a sum greater than 9(vi) an even number on first(vii) an even number on one and a multiple of 3 on the other(viii) neither 9 nor 11 as the sum of the numbers on the faces(ix) a sum less than 6(x) a sum less than 7(xi) a sum more than 7(xii) at least once(xiii) a number other than 5 n any dice.(xiv) even number on each die(xv) 5 as the sum(xvi) 2 will come up at least once(xvii) 2 will not come either time

Sample space = 36

(i) n(E) = 5 (ii) n(E) = 6 (iii) n(E) = 3 (iv) (v) (vi) (vii) (viii) Number of event with sum 9 or 11 = 6

Number of events of not getting a sum of either 9 or 11 = 36 – 6 = 30 (ix) (x) (xi) (xii) (xiii) Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Smart Revision | Quiz on Probability37 mins  NCERT | How Probability Can Help You Score Marks?44 mins  Introduction to Probability53 mins  NCERT | Quiz on Probability47 mins  Quiz | Imp. Qs. of Probability37 mins  Solve RD Sharma Problems 2x Faster30 mins  Let's understand Probability40 mins  When Chance is called Probability48 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses 