Answer :

Given that two dice are drawn together i.e. n(S)= 36


Where S is sample space


Also given that


E = a of total 4


E = {(2,2), (3,1), (1,3)}


n(E) = 3


And F= a total of 9 or more


F = {(3,6), (6,3), (4,5), (5,4), (6,4), (4,6), (6,5), (6,6), (5,5), (5,6)}


n(F)=10


And,


G = a total divisible by 5


G = {(1,4), (4,1), (2,3), (3,2), (4,6), (6,4), (5,5)}


n(G) = 7


Here, (E Ո F) = φ AND (E Ո G) = φ


Also, (F Ո G) = {(4,6), (6,4), (5,5)}


n (F Ո G) = 3 and (E Ո F Ո G) = φ






And,


So,


P (F Ո G) ≠ P(F). P(G)


hence, there is no pair which is independent


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