Answer :

True(T)

Here, we have



This implies B + C is either 2 or two digit number whose one’s


digit is 2.


Its given that B ≠ 0, C ≠ 0,so B + C is a two digit number whose one’s digit is 2.


When B = C = 1, then A should be 3 so that we have



But in this case A + B + C ≠ 14,so B = C = 1 cannot happen.


(I)Here either B or C should be 5 or 7 and A should be 3 so that


A + B + C = 14.


(II)If B = C = 6 and A = 2, then



and A + B + C = 14


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