*Answer :*

*True(T)*

*Here it’s given a is divisible by b,*

Let b = x1.x2 ,where x1 and x2 are prime numbers.

Since a is divisible by b,a is a multiple of b.

i.e. a = p.b

⇒ a = p.x1.x2

Or a = cx2 = dx1 where c = px1 and d = px2

⇒ a is a multiple of p1 as well as p2.

Hence a is divisible by each factor of b.

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