Answer :
True(T)
Here it’s given a is divisible by b,
Let b = x1.x2 ,where x1 and x2 are prime numbers.
Since a is divisible by b,a is a multiple of b.
i.e. a = p.b
⇒ a = p.x1.x2
Or a = cx2 = dx1 where c = px1 and d = px2
⇒ a is a multiple of p1 as well as p2.
Hence a is divisible by each factor of b.
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