Q. 204.7( 3 Votes )

# A hollow cylindrical pipe has inner circumference 44 dm and outer 45 dm. Find the cost of painting it from both sides at Rs2 per m2. If its length is 3.5 m.

Given ; inner circumference = 2πr1 = 44

r1 = 7dm

outer circumference = 2πr2 = 45

r2 = 7.16dm

height (h) = 3.5m = 35 dm

Total area of painting pipe = inner curved surface area + outer curved surface area of cylinder

= 2π r1h + 2π r2h

= 2π h(r1 + r2)

= 22 × 14.16

= 311.52 dm2

As, cost of 1 dm2 = Rs 2

So, cost of 311.52 dm2 = Rs(2 × 311.52) = Rs. 623.04

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Surface Area and Volumes43 mins
RD Sharma | Imp Concepts : Surface Area And Volumes43 mins
RD Sharma | Surface Area And Volumes43 mins
IMP Formula's and Qs For Surface Area and Volumes45 mins
RD Sharma | Imp. Qs. From Surface Area And Volumes47 mins
Quiz | Surface Area and Volumes42 mins
Surface Area and Volume49 mins
Areas Related to Circle36 mins
Quiz | Areas Related to Circles43 mins
Foundation | Let's Understand Some High Level Concepts41 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses