Answer :
Let E1, E2, E3 and E4 are the events that the first, second, third and fourth card is king respectively.
As there are 4 kings,
when 1 king is taken out kings left are 3 and total cards will be 51.
So, probability of drawing a king when one king has been taken out is:
Now when 2 kings taken out 2 kings are left, and 50 cards are there.
So, probability of drawing a king when two kings have been taken out is:
Now when 3 kings taken out 1 king is left, and 49 cards are there.
So, probability of drawing a king when three kings have been taken out is:
Probability that all 4 cards are king is:
∴P (E1 Ո E2 Ո E3 Ո E4) = p(E1). P(E2|E1). P (E3|E1 Ո E2). P [E4|(E1 ՈE2 Ո E3 ՈE4)]
=
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