Answer :

Let E_{1}, E_{2}, E_{3} and E_{4} are the events that the first, second, third and fourth card is king respectively.

As there are 4 kings,

when 1 king is taken out kings left are 3 and total cards will be 51.

So, probability of drawing a king when one king has been taken out is:

Now when 2 kings taken out 2 kings are left, and 50 cards are there.

So, probability of drawing a king when two kings have been taken out is:

Now when 3 kings taken out 1 king is left, and 49 cards are there.

So, probability of drawing a king when three kings have been taken out is:

Probability that all 4 cards are king is:

∴P (E_{1} Ո E_{2} Ո E_{3} Ո E_{4}) = p(E_{1}). P(E_{2}|E_{1}). P (E_{3}|E_{1} Ո E2). P [E_{4}|(E_{1} ՈE_{2} Ո E_{3} ՈE_{4})]

=

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