Answer :

Given,

Depth(d) = 12dm = 1.2m

Width(w) = 30dm = 3m

Velocity of water (v) = 20km/h = 20,000 m/h

time (t) = 30minute = 0.5 hour

⇒ The volume of water = w × d × length

Here length becomes speed × time = v × t

Volume of water = w × d × v × t

= 1.2 × 3 × 20000 × 0.5

= 36000 m^{3}

Now,

Let the area irrigated be x

And Desired standing water = 9cm = 0.09m

Since volume of water will be same

⇒ 36000 = x × 0.09

⇒ x = 400000

So, area irrigated by the canal is 400000 m^{2}

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