Answer :
Let X is the random variable of profit per throw.
Probability of getting any number on dice is .
Since, she loss Rs 1 on getting any of 2, 4 or 5.
So, at X= -1,
P(X) = P (2) +P(4) +P(5)
Similarly, =1 if dice shows of either 1 or 6.
P(X) = P (1) +P (6)
and at X=4 if die shows a 3
P(X) = P (3)
∴ Player’s expected profit = E(X)= XP(X)
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