# If x + y + z = 6 and z is an odd digit, then the three-digit number xyz isA. an odd multiple of 3B. odd multiple of 6C. even multiple of 3D. even multiple of 9

Since the sum of the digits of xyz i.e x + y + z = 6

By divisibility test of three the number xyz is divisible by 3.

Also the last digit (z) is odd digit.

xyz is the odd multiple of three.

Hence the option (a) is correct.

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