Q. 1065.0( 1 Vote )

# Fill in the blanks in the following question:If X follows binomial distribution with parameters n = 5, p and P (X = 2) = 9.P (X = 3), then p = ___________

p = 1/10

As n = 5 {representing no. of trials}

p = probability of success

As it is a binomial distribution.

probability of failure = q = 1 – p

Given,

P(X = 2) = 9.P(X = 3)

The binomial distribution formula is:

P(x) = nCx Px (1 – P)n – x

Where:

x = total number of “successes.”

P = probability of success on an individual trial

n = number of trials

Using binomial distribution,

5C2p2q5-2 = 95C3p3q5-3

10p2q3 = 9×10p3q2

10q = 90p {As , p≠0 and q ≠ 0}

q = 9p

1-p = 9p 10p = 1

p = 1/10

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