Answer :

According to the question the number can be of form abcabc.

The general form of number abcabc is


Abcabc = 100000a + 10000b + 1000c + 100a + 10b + c.


Abcabc = 100000a + 100a + 10000b + 10b + 1000c + c.


Abcabc = 100100a + 10010b + 1001c.


Abcabc = 1001(100a + 10b + c).


Clearly we can see that abcabc is divisible by 1001 because 1001 is one of the factor of it.


Option (d) is correct.

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