# In the given figure, PA and PB are two tangents to the circle with center O. If ∠APB = 50° then what is the measure of ∠OAB.

In the given figure, PA and PB are two tangents from common point P

PA = PB

[Tangents drawn from an external point are equal]

PBA = PAB

[Angles opposite to equal angles are equal] [1]

By angle sum property of triangle in APB

APB + PBA + PAB = 180°

50° + PAB + PAB = 180° [From 1]

2PAB = 130°

PAB = 65° [2]

Now,

OAP = 90°

[Tangents drawn at a point on circle is perpendicular to the radius through point of contact]

OAB + PAB = 90°

OAB + 65° = 90° [From 2]

OAB = 25°

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