Answer :

We are given with perimeter of triangle and ratio of its sides. We need to construct a triangle using the given information.

Steps of construction:


1. Draw a line segment using ruler and locate points X and Y such that XY = 14 cm.



2. Draw a ray XZ, making an acute angle with XY and drawn in the downward direction.



Here, YXZ < 90° obviously.


3. From X, locate (2 + 4 + 5) = 11 points at equal distances along XZ.



4. Mark points L, M, N on XZ such that XL = 2 parts, LM = 4 parts and MN = 5 parts.



5. Now, join NY. Through L and M, draw LQ NY and MR NY, intersecting XY at Q and R respectively.



6. With Q as centre and QX as radius, draw a circle or a semicircle or an arc. Keep one end of compass fixed at Q, and then draw a fine circle or arc with it.



7. With R as centre and RY as radius, draw another circle or semicircle or arc cutting the previous arc at P. Keep one end of the compass fixed at R, and then draw a fine circle or arc with it.



8. Finally, join PQ and PR.



Thus, PQR is the required triangle.


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