Answer :
Area of rectangle (ABCD) = BC × CD
⇒ Area of rectangle (ABCD) = 51 × 25 = 1275 cm2
Area of trapezium PQCD = 5/6 × Area of rectangle (ABCD)
⇒ Area of trapezium PQCD = 5/6 × 1275 = 1062.5 cm2
Given that QC:PD = 9:8
Let QC = 9x and PD = 8x
Area (PQCD) =
⇒ Area (PQCD) =
⇒ 1062.5 =
⇒ 85 = 17x
⇒ x = 5cm
QC = 9x = 45cm
PD = 8x = 40 cm
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