Answer :

Area of rectangle (ABCD) = BC × CD

Area of rectangle (ABCD) = 51 × 25 = 1275 cm2


Area of trapezium PQCD = 5/6 × Area of rectangle (ABCD)


Area of trapezium PQCD = 5/6 × 1275 = 1062.5 cm2


Given that QC:PD = 9:8


Let QC = 9x and PD = 8x


Area (PQCD) =


Area (PQCD) =


1062.5 =


85 = 17x


x = 5cm


QC = 9x = 45cm


PD = 8x = 40 cm


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