Answer :

Let the length breath and height be the external dimension of an open box and thickness be


The volume of metal used in box = Volume of external box - Volume of internal box


For external box,


Length, l = 36 cm


Breadth, b = 25 cm


Height, h = 16.5 cm


We know that,


Volume of cuboid = lbh


Where, l, b and h are the length, breadth and height of tank respectively


Volume of external box = 36(25)(16.5) = 14850 cm3


Now,


As the box is open from top,


For internal box,


Length, l' = Length of external box - 2(thickness of box) = 36 - 2(1.5) = 33 cm


[i.e. the thickness of two sides is deduced]


Breadth, b' = Breadth of external box - 2(thickness of box) = 25 - 2(1.5) = 22 cm


[i.e. the thickness of two sides is deduced]


Height, h' = Height of external box - thickness of box = 16.5 - 1.5 = 15 cm


[i.e. the thickness of bottom is reduced]


Volume of internal box = 33(22)(15) = 10890


So,


Volume of metal in box = 14850 - 10890 = 3960 cm3


Also,


1 cm3 weighs 7.5 g


3960 cm3 weighs 3960(7.5) = 29,700 g


So,


The weight of box is 29,700 g i.e. 29.7 kg


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