Answer :
If LHS is
(x – 4)2
Then RHS would be
⇒ (x – 4)2
= (x)2 + 42 – 2 × x × 4
= x2 + 16 – 8x
The error is x2 + 16 – 8x instead of x2 – 16
Hence (x – 4)2 = x2 + 13 – 8x
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