Answer :
If LHS is
x2– 5x + 6
Then RHS would be
⇒ x2– 5x + 6
Putting x = (-3)
= (–3)2 –5 (–3) + 6
= 9 + 15 + 6
= 30
The error is + 15 instead of (-15) and end results to 30 instead of 0
Hence putting x = (-3) in x2– 5x + 6 results to 30
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